First, calculate the moles of HgO :
n(HgO)=‌=0.001‌molAccording to the reaction:
HgO+4I−+H2O→HgI42−+2OH−Each mole of HgO produces 2 moles of hydroxide ions
(OH−). So, the moles of
OH− formed are:
n(OH−)=2×0.001=0.002‌molNext, these hydroxide ions are titrated with HCl . The reaction between
HCl−and
OH−is:
HCl+OH−→H2O This reaction occurs in a 1:1 mole ratio. Therefore, 0.002 moles of HCl are needed to neutralize the hydroxide produced.
Given that the concentration of HCl is 0.01 M , the volume of HCl required is calculated by:
Converting liters to milliliters:
0.2L=200‌mLThus, 200 mL of 0.01 M HCl is required at the equivalence point.
The correct answer is Option B: 200 mL .