Xavier Aptitude Test 2023 Paper

Let the positive integers Raju & Sarita chose be 'r' & 's'.
After doing the given operations, the final numbers they get are ‌

2r−20

5&

‌

2s−20

5

Adding results we get, ‌

2r−20

5

+‌

2s−20

5

=16
‌2r−20+2s−20=80
‌2r+2s=80+40+40=120
‌r+s=60
For maximum value of ∣r-s|, one of ' r ' & 's' has to be maximum and other has to be minimum.
As r& s are positive integers minimum value they can take is " 1 ".
If r=1, then s=59
|r−s|=|1−59|=58
If s=1, then r=59
|r−s|=|59−1|=58
Hence maximum value of |r−s| is 58 . Option B is correct.