NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

Question : 22

Total: 36

If the speed of light is 3.0 × 108ms–1, calculate the distance covered by light in 2.00 ns.

Solution:

Speed of light = 3.0 × 108ms–1
Distance covered by light in 2.00 ns = 3.0 × 108 × 2 × 10–9
= 6.00 × 10–1 m = 0.600 m

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