NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 50
Total: 106
Find a G.P. for which sum of the first two terms is – 4 and the fifth term is 4 times the third term.
Solution:  
Let a1,a2 be first two terms and a3,a5 be third and fifth terms respectively.
according to question
a1+a2 = – 4 ⇒ a + ar = – 4 ⇒ a(1 + r) = – 4 ....(i)
and a5 = 4a3ar4 = 4ar2r2 = 4 ⇒ r = ± 2
If r = 2, then (i) becomes a(1 + 2) = – 4 ⇒a =
If r = – 2, then (i) becomes a (1 – 2) = – 4 ⇒ a = 4
When a =
4
3
and r = 2, then G.P. is
4
3
,
8
3
,
16
3
, ...
When a = 4 and r = – 2, then G.P. is 4, – 8, 16, – 32, ........ .
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