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AIEEE 2007 Solved Paper
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© examsnet.com
Question : 23
Total: 118
The energies of activation for forward and reverse reactions for
A
2
+
B
2
⇋
2
A
B
are
180
kJ
mol
−
1
and
200
kJ
mol
−
1
respectively. The presence of catalyst lowers the activation energy of both (forward and reverse) reactions by
100
kJ
mol
−
1
. The enthalpy change of the reaction
(
A
2
+
B
2
→
2
AB
)
in the presence of catalyst will be (in
kJ
mol
−
1
)
300
120
200
20
Validate
Solution:
∆
H
R
=
E
f
−
E
b
=
180
−
200
=
−
20
kJ
/
mol
The nearest correct answer given in choices may be obtained by neglecting sign.
© examsnet.com
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