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AIEEE 2008 Solved Paper
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© examsnet.com
Question : 18
Total: 104
The vapour pressure of water at
20
∘
C
is
17.5
mm
Hg
. If
18
g
of glucose
(
C
6
H
12
O
6
)
is added to
178.2
g
of water at
20
∘
C
, the vapour pressure of the resulting solution will be
17.675
mm
Hg
15.750
mm
Hg
16.500
mm
Hg
17.325
mm
Hg
Validate
Solution:
NOTE : On addition of glucose to water, vapour pressure of water will decrease. The vapour pressure of a solution of glucose in water can be calculated using the relation
P
∘
−
P
S
P
S
=
Moles of glucose in solution
moles of water in solution
or
17.5
−
P
S
P
S
=
18
/
180
178.2
/
18
[as
P
∘
=
17.5
]
or
17.5
−
P
S
=
0.1
×
P
S
9.9
or
P
S
=
17.325
mm
Hg
.
© examsnet.com
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