At 80^{∘} {\C}, the vapour pressure of pure liquid ' A ' is 520 {\mm} {\Hg} and that of pure liquid ' B ' is 1000 {\mm} {\Hg}. If a mixture solution of ' A ' and ' B ' boils at 80^{∘} {\C} and 1 {\atm} pressure, the amount of ' A ' in the mixture is ( 1 {\atm}=760 {\mm} {\Hg} )

Question

At 80^{∘}  {\C}, the vapour pressure of pure liquid ' A ' is 520  {\mm}  {\Hg} and that of pure liquid ' B ' is 1000  {\mm}  {\Hg}. If a mixture solution of ' A ' and ' B ' boils at 80^{∘}  {\C} and 1  {\atm} pressure, the amount of ' A ' in the mixture is ( 1  {\atm}=760  {\mm}  {\Hg} )

Examsnet · Accepted Answer

Correct Answer is : 50 mol percent

AIEEE 2008 Solved Paper