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JEE Advanced 2020 Full Test 1 Paper 2
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© examsnet.com
Question : 1
Total: 54
A particle of mass
2
k
g
is moving along
x
-axis with a velocity of
5
m
∕
s
. It crosses the origin at
t
=
0
.
A time varying force whose variation is as shown starts acting on a particle at
t
=
1
sec. For this situation, mark out the correct statement.
the particle will come to rest instantaneously at
t
=
6.8
s
e
c
the final velocity of the particle will be
18
m
∕
s
.
work done by the force
F
on the particle is
375
J
all of the above
Validate
Solution:
Use
4
∫
0
F
d
t
=
m
v
−
m
(
5
)
work
F
=
1
2
m
v
2
−
1
2
m
(
5
)
2
© examsnet.com
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