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JEE Advanced 2020 Full Test 1 Paper 2
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© examsnet.com
Question : 2
Total: 54
Two springs, each of unstretched length
20
c
m
but having different spring constants
K
1
=
1000
N
∕
m
and
K
2
=
3000
N
∕
m
are attached to two opposite faces of a block of mass
m
=
100
g
kept on a smooth horizontal surface as shown in the figure. The outer ends of the two springs are now attached to two pins
P
1
&
P
2
whose locations are shown in the figure, as a result of this, the block acquires a new equilibrium position. The block has been displaced by small amount from its equilibrium position and released to perform simple harmonic motion, then
new equilibrium position is at
35
c
m
from
P
1
and time period of simple harmonic motion is
π
100
s
e
c
new equilibrium position is at
20
c
m
from
P
1
and time period of simple harmonic motion is
π
100
sec.
new equilibrium position is at
35
c
m
from
P
1
and time period of simple harmonic motion is
π
26
sec.
new equilibrium position is at
30
c
m
from
P
1
and time period of simple harmonic motion is
π
26
sec.
Validate
Solution:
For equilibrium of the block
K
1
(
x
0
+
30
−
20
)
=
K
2
[
30
−
x
0
−
20
]
⇒
x
0
=
5
c
m
T
=
2
π
√
m
K
i
+
K
2
=
π
100
s
e
c
© examsnet.com
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