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JEE Advanced 2020 Full Test 4 Paper 2
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© examsnet.com
Question : 1
Total: 54
A cubical block of wood of edge
10
c
m
and mass
0.92
k
g
floats on a tank of water with oil of rel. density 0.6 to a depth of
4
c
m
above water. When the block attains equilibrium with four of its sides edges vertical
1
c
m
of it will be above the free surface of oil
5
c
m
of it will be under water
2
c
m
of it will be above the common surface of oil and water
8
c
m
of it will be under water
Validate
Solution:
[
ρ
w
×
10
−
2
×
h
]
+
[
ρ
0
×
10
−
2
(
0.1
−
h
)
]
=
0.92
⇒
h
=
8
c
m
© examsnet.com
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