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JEE Advanced 2020 Full Test 4 Paper 2
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© examsnet.com
Question : 2
Total: 54
A disc of radius
R
rolls on a horizontal surface with linear velocity
V
and angular velocity
ω
.
There is a point
P
on circumference of disc at angle
θ
with upward vertical diameter measured anticlockwise see figure, which has a vertical velocity. Here
θ
is equal to
π
+
sin
−
1
V
R
ω
π
2
−
sin
−
1
V
R
ω
π
−
cos
−
1
V
R
ω
π
+
cos
−
1
V
R
ω
Validate
Solution:
Particle
P
will have a velocity in vertical direction. i.e.
R
ω
cos
α
=
V
α
=
cos
−
1
V
R
ω
Required angle
θ
is
θ
=
π
−
α
=
π
−
cos
−
1
V
R
ω
And in second case
R
ω
cos
α
=
V
α
=
cos
−
1
V
R
ω
,
θ
=
π
+
cos
−
1
V
R
ω
© examsnet.com
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