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JEE Main 27 June 2022 Shift 2 Solved Paper
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© examsnet.com
Question : 39
Total: 90
A lead bullet penetrates into a solid object and melts. Assuming that
40
%
of its kinetic energy is used to heat it, the initial speed of bullet is :
(Given : initial temperature of the bullet
=
127
∘
C
, Melting point of the bullet
=
327
∘
C
, Latent heat of fusion of lead
=
2.5
×
10
4
J
kg
−
1
, Specific heat capacity of lead
.
=
125
J
∕
kg
K
)
[27-Jun-2022-Shift-2]
125
ms
−
1
500
ms
−
1
250
ms
−
1
600
ms
−
1
Validate
Solution:
2
5
×
1
2
m
v
2
=
m
L
+
m
s
∆
T
⇒
v
2
5
=
2.5
×
10
4
+
125
+
200
⇒
v
2
5
=
5
×
10
4
⇒
v
=
500
m
∕
s
© examsnet.com
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