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JEE Main 27 June 2022 Shift 2 Solved Paper

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Question : 40

Total: 90

The equation of a particle executing simple harmonic motion is given by x=sin‌π(t+‌

)‌m. At t=1s, the speed of particle will be
(Given : π=3.14 )

[27-Jun-2022-Shift-2]

0‌cm‌s−1
157‌cm‌s−1
272‌cm‌s−1
314‌cm‌s−1

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