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JEE Main Chemistry Class 11 Some Basic Concepts of Chemistry Part 1 Questions
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© examsnet.com
Question : 67
Total: 100
A sample of a hydrate of barium chloride weighing
61
g
was heated until all the water of hydration is removed. The dried sample weighed
52
g
. The formula of the hydrated salt is : (atomic mass,
B
a
=
137
a
m
u
,
C
l
=
35.5
amu)
[Online April 10, 2015]
B
a
C
l
2
⋅
4
H
2
O
B
a
C
l
2
⋅
3
H
2
O
B
a
C
l
2
H
2
O
B
a
C
l
2
−
2
H
2
O
Validate
Solution:
Weight of hydrated
B
a
C
l
2
=
61
g
Weight of anhydrous
B
a
C
l
2
=
52
g
Loss in mass
=
9
g
Assuming
B
a
C
l
2
x
H
2
O
as hydrate
Mass of
H
2
O
=
9
g
Moles of
H
2
O
=
9
18
=
0.5
m
o
l
Grass molecular wt. of
B
a
C
l
2
=
208
g
∕
m
o
l
.
%
of
H
2
O
in this hydrated
B
a
C
l
2
=
9
61
×
100
=
14.75
%
%
of
H
2
O
in
B
a
C
l
2
⋅
x
H
2
O
=
18
x
208
+
18
x
×
100
Thus,
18
x
208
+
18
x
×
100
=
14.75
On solving
x
=
2
Hence, the formula of hydrated salt is
B
a
C
l
2
.2
H
2
O
© examsnet.com
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