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JEE Main Chemistry Class 11 Some Basic Concepts of Chemistry Part 1 Questions
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© examsnet.com
Question : 68
Total: 100
A
+
2
B
+
3
C
⇌
A
B
2
C
3
Reaction of
6.0
g
of
A
,
6.0
×
10
23
atoms of
B
, and
0.036
mol of
C
yields
4.8
g
of compound
A
B
2
C
3
. If the atomic mass of
A
and
C
are 60 and
80
a
m
u
, respectively, the atomic mass of
B
is
(
Avogadro
n
o
.
=
6
×
10
23
)
:
[Online April 11, 2015]
50
a
m
u
60
a
m
u
70
a
m
u
40
a
m
u
Validate
Solution:
A
+
3
B
+
3
C
⇌
A
B
2
C
3
.......(i)
No. of moles of
A
=
6.0
g
60
g
∕
m
o
l
=
0.1
m
o
l
No. of moles of
B
=
6.00
×
10
23
6.000
×
10
23
=
1
m
o
l
No. of moles of
C
=
0.036
Therefore,
C
is the limiting reagent,
The number of moles of product formed
=
0.036
3
=
0.012
m
o
l
The expression for the molar mass is Molar mass
=
Given mass
mole of product
60
+
(
2
×
x
)
+
(
3
×
80
)
=
4.8
0.012
x
=
50
a
m
u
Hence, atomic mass of B is 50 amu
© examsnet.com
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