Given circle is: x2+y2+2x−4y−4=0 ∴ its centre is (-1,2) and radius is 3 units. Let A=(x,y) be the centre of the circle C ∴
x−1
2
=2⇒x=5 and
y+2
2
=2⇒y=2 So the centre of C is (5,2) and its radius is 3 ∴ equation of centre C is: x2+y2−10x−4y+20=0 ∴ The length of the intercept it cuts on the x -axis =2√g2−c=2√25−20=2√5