Equation of the line passing through the points (2,3) and (4,5) is y−3=(
5−3
4−2
)x−2⇒x−y+1=0.....(i) Equation of the perpendicular line passing through the midpoint (3,4) is x+y−7=0 . . . (ii) .....( ii) Lines (1) and (2) intersect at the center of the circle. So, the center of the circle is (3,4) Therefore, the radius is √(x2−x1)2+(y2−y1)2=√(2−3)2+(3−4)2=√2 units.