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JEE Main Physics Class 11 Kinetic Theory of Gases Part 2 Questions
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© examsnet.com
Question : 30
Total: 51
If the r.
m
. s speed of chlorine molecule is
490
m
∕
s
at
27
∘
C
, the
r
.
m
.
s
speed of argon molecules at the same temperature will be (Atomic mass of argon
=
39.9
u
, molecular mass of chlorine
=
70.9
u
)
[12-Apr-2023 shift 1]
651.7
m
∕
s
451.7
m
∕
s
551.7
m
∕
s
751.7
m
∕
s
Validate
Solution:
Molar mass of chlorine
=
70.9
u
Atomic mass of argon
=
39.9
u
V
rms
=
√
3
RT
m
V
rms
∝
√
1
m
V
rmschlorine
V
rmsarg on
=
√
m
arg on
m
chlorine
490
V
rmsargon
=
√
39.9
70.9
V
rmsargon
=
490
×
1.33
V
msargon
=
651.7
m
∕
s
e
c
© examsnet.com
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