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JEE Main Physics Class 11 Kinetic Theory of Gases Part 2 Questions
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© examsnet.com
Question : 31
Total: 51
The rms speed of oxygen molecule in a vessel at particular temperature is
(
1
+
5
x
)
1
2
v
, where
v
is the average speed of the molecule. The value of
x
will be: (Take
π
=
22
7
)
[13-Apr-2023 shift 1]
28
27
8
4
Validate
Solution:
V
mms
=
√
3
RT
M
V
avg
=
v
=
√
8
RT
π
M
V
mms
=
√
3
π
8
v
V
mms
=
√
3
8
×
22
7
v
=
(
33
28
)
1
∕
2
v
V
mms
=
(
1
+
5
28
)
1
∕
2
v
x
=
28
© examsnet.com
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