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JEE Main Physics Class 11 Laws Of Motion Part 1 Questions

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Question : 29

Total: 100

A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied horizontally at the midpoint of the rope such that the top half of the rope makes an angle of 45° with the vertical. Then F equals:
(Take g = 10 ms‌–2 and the rope to be massless)

[7 Jan. 2020 II]

100 N
90 N
70 N
75 N

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