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JEE Main Physics Class 11 Laws Of Motion Part 1 Questions
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© examsnet.com
Question : 30
Total: 100
An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg. The mass of the elevator itself is 920 kg and it moves with a constant speed of 3 m/s. The frictional force opposing the motion is 6000 N. If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator (g =10 m/s
2
) must be at least:
[7 Jan. 2020 II]
56300 W
62360 W
48000 W
66000 W
Validate
Solution:
Net force on the elevator
=
force on elevator + frictional force
⇒
F
=
(
10
m
+
M
)
g
+
f
where,
m
=
mass of person,
M
=
mass of elevator,
f
=
frictional force
⇒
F
=
(
10
×
68
+
920
)
×
9.8
+
600
⇒
F
=
22000
N
⇒
P
=
F
V
=
22000
×
3
=
66000
W
© examsnet.com
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