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Test Index
JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 1 Questions
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Question : 15
Total: 100
An experiment takes 10 minutes to raise the temperature of water in a container from 0ºC to 100ºC and another 55 minutes to convert it totally into steam by a heater supplying heat at a uniform rate. Neglecting the specific heat of the container and taking specific heat of water to be 1 cal / g ºC, the heat of vapourization according to this experiment will come out to be :
[Online April 11, 2015]
560 cal/ g
550 cal/ g
540 cal/ g
530 cal/ g
Validate
Solution:
As
P
t
=
m
C
Δ
T
So,
P
×
10
×
60
=
m
C
100
......(i)
and
P
×
55
×
60
=
m
L
.......(ii)
Dividing equation (i) by (ii) we get
10
55
=
C
×
100
L
∴
L
=
550
cal.
/
g
.
© examsnet.com
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