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JEE Main Physics Class 11 Properties of Solids and Liquids Questions Part 1 Questions
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Question : 16
Total: 100
The pressure that has to be applied to the ends of a steel wire of length 10 cm to keep its length constant when its temperature is raised by 100ºC is:
(For steel Young's modulus is
2
×
10
11
N
m
−
2
and coefficient of thermal expansion is
1.1
×
10
−
5
K
−
1
)
[2014]
2.2
×
10
8
P
a
2.2
×
10
9
P
a
2.2
×
10
7
P
a
2.2
×
10
6
P
a
Validate
Solution:
Young's modulus
Y
=
stress
strain
stress
=
Y
×
strain
Stress in steel wire
=
Applied pressure
Pressure
=
stress
=
Y
×
strain
Strain
=
Δ
L
L
=
α
Δ
T
(As length is constant)
=
2
×
10
11
×
1.1
×
10
−
5
×
100
=
2.2
×
10
8
P
a
© examsnet.com
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