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JEE Main Physics Class 11 Thermodynamics Part 2 Questions
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© examsnet.com
Question : 36
Total: 82
A body cools from
60
∘
C
to
40
∘
C
in 6 minutes. If, temperature of surroundings is
10
∘
C
. Then, after the next 6 minutes, its temperature will be
∘
C
.
[29-Jan-2023 Shift 1]
Your Answer:
Validate
Solution:
By average form of Newton's law of cooling
20
6
=
k
(
50
−
10
)
. . . (i)
40
−
T
6
=
K
(
40
+
T
2
−
10
)
. . . (ii)
From equation (i) and (ii)
20
40
−
T
=
40
10
+
T
∕
2
10
+
T
2
=
80
−
2
T
5
T
2
=
70
⇒
T
=
28
∘
C
© examsnet.com
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