∆Q=184×103 m=0.600kg at −12∘C S=222.3J∕kg∕∘C L=336×103J∕kg Q1=0.600×2222.3×12=16000.56J Remaining heat ∆Q1=184000−16000.56 =167999.44J For meeting at 0∘C ∆Q2=0.600×336000=201600J needed ∴100% ice is not melted Amount of ice melted 167999.44=m×336000=0.4999kg ∴ mass of water =0.4999kg Mass of ice =0.1001 ∴ Ratio =