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JEE Main Physics Class 12 Alternating Currents Part 2 Questions
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© examsnet.com
Question : 41
Total: 75
In a series
L
R
circuit with
X
L
=
R
. power factor is
P
1
. If a capacitor of capacitance
C
with
X
C
=
X
L
is added to the circuit the power factor becomes
P
2
. The ratio of
P
1
to
P
2
will be :
[30-Jan-2023 Shift 1]
1
:
3
1
:
√
2
1
:
1
1
:
2
Validate
Solution:
P
=
R
Z
⇒
P
1
=
R
√
R
2
+
X
L
2
=
R
R
√
2
(
as
X
L
=
R
)
P
1
=
1
√
2
P
2
=
R
√
R
2
+
(
X
L
−
X
L
)
2
=
P
2
=
1
P
1
P
2
=
1
√
2
© examsnet.com
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