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JEE Main Physics Class 12 Alternating Currents Part 2 Questions
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© examsnet.com
Question : 42
Total: 75
In the given circuit, rms value of current
(
I
rms
)
through the resistor
R
is :
[30-Jan-2023 Shift 2]
2
A
1
2
A
20
A
2
√
2
A
Validate
Solution:
z
=
√
100
2
+
(
200
−
100
)
2
=
100
√
2
Ω
i
rms
=
V
rms
z
=
200
√
2
100
√
2
=
2
A
© examsnet.com
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