Given: f(x)=sin2(x)+3cosx−5 Let's calculate f(−x) ⇒f(−x)=sin2(−x)+3cos(−x)−5 ⇒f(−x)=(−1)2sin2(x)+3cos(x)−5 --------------(∵ sin x is an odd function and cos x is an even function) ⇒f(−x)=f(x) So, f(x) is an even function. Hence, option A is the correct answer.