Here, we have to find the distance of the point (2, 3, 4) from the plane 3x - 6y + 2z + 11 = 0 As we know that, the perpendicular distance of a plane ax + by + cz + d = 0 from a point P (x1,y1,z1) is given by: D =|
ax1+by1+cz1+d
√a2+b2+c2
| Here, x1=2,y1=3,z1=4,a=3,b=−6 and c=2So, the required distance between the given point and plane is D=|